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04-26-2006, 06:33 PM
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Fish Food
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Join Date: Apr 2006
Posts: 5
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Adding Probabilities
I apologize if this has been discussed already, but I did a search and couldn't find anything.
I am trying to figure out what the probability is that someone else has a better hand than you. I am able to figure out how likely each person is to have a better hand than you, but I am not sure how to apply that to multiple people. Can you simply multiply the probability that each person has a hand better than yours times the number of players?
For example. If there is a 10% chance that each person has a better hand than yours, and there are 5 players sitting at your table, is the probability that at least one of those players has a better hand than you 50%?
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04-26-2006, 06:34 PM
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NL20 Grinder...
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Join Date: Jul 2005
Location: Portland, OR
Posts: 7,523
Limits Played: $0.10-$0.25 NL
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Quote:
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Originally Posted by purus
I apologize if this has been discussed already, but I did a search and couldn't find anything.
I am trying to figure out what the probability is that someone else has a better hand than you. I am able to figure out how likely each person is to have a better hand than you, but I am not sure how to apply that to multiple people. Can you simply multiply the probability that each person has a hand better than yours times the number of players?
For example. If there is a 10% chance that each person has a better hand than yours, and there are 5 players sitting at your table, is the probability that at least one of those players has a better hand than you 50%?
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If I am correct, there is no real way to figure that out. The best you can do is figure out the win % for your current hand vs. a certain number of people.
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04-26-2006, 06:38 PM
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Fish Food
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Join Date: Apr 2006
Posts: 5
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Well it's really just a question of probabilities. Forget about Poker for a second. How do you add probabilities? When you flip a coin, you know you have a 50% chance of getting tails. If you flip two coins (or more), what is the probability that at least one of them will be tails?
I am thinking that you can just add the probabilities together, so two coins would be 100%, 3 - 150%, 4 - 200%, etc.
I am a little uneasy about this though. Something tells me I am missing something...
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04-26-2006, 06:40 PM
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change my title babo
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Join Date: May 2004
Posts: 6,758
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P(A)+P(B)-P(A(intersect)b)
__________________
“There's no sense in being precise when you don't even know what you're talking about.” - John von Neumann
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04-26-2006, 06:41 PM
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NL20 Grinder...
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Join Date: Jul 2005
Location: Portland, OR
Posts: 7,523
Limits Played: $0.10-$0.25 NL
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Quote:
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Originally Posted by purus
Well it's really just a question of probabilities. Forget about Poker for a second. How do you add probabilities? When you flip a coin, you know you have a 50% chance of getting tails. If you flip two coins (or more), what is the probability that at least one of them will be tails?
I am thinking that you can just add the probabilities together, so two coins would be 100%, 3 - 150%, 4 - 200%, etc.
I am a little uneasy about this though. Something tells me I am missing something...
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You are definitely missing something. I just dont know what it is.
And let me be the first to welcome you to the forum.
And THANK YOU THANK YOU THANK YOU, for checking the search before posting this. You dont realize how much verbal abuse you saved yourself by doing that.
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04-26-2006, 06:41 PM
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NL20 Grinder...
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Join Date: Jul 2005
Location: Portland, OR
Posts: 7,523
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Quote:
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Originally Posted by bonchkid
P(A)+P(B)-P(A(intersect)b)
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Enough of your nonsense. You know humans cant read that jargon. 
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04-26-2006, 06:43 PM
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Fish Food
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Join Date: Apr 2006
Posts: 5
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Quote:
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Originally Posted by KRE8R
And THANK YOU THANK YOU THANK YOU, for checking the search before posting this. You dont realize how much verbal abuse you saved yourself by doing that.
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I watched that little video. It was hilarioius.
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04-26-2006, 06:46 PM
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NL20 Grinder...
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Join Date: Jul 2005
Location: Portland, OR
Posts: 7,523
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Quote:
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Originally Posted by purus
I watched that little video. It was hilarioius.
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Good GOD, you may be the smartest new member I have ever met.
I didnt even watch the video until someone told me too... 
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04-26-2006, 06:48 PM
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Fish Food
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Join Date: Apr 2006
Posts: 5
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Wait, I think I figured it out. 2 coins would be 75%, not 100%. I thought it was a little weird that it would go over 100%, because there is always a chance that you will get all heads.
I think that the formula is that for each coin you add, you add the original percent devided by the new total of coins. So 1 coin is 50%, 2 is 50% + (50% / 2), and three coins is 50% + (50% / 2) + (50% / 3). That way it will never reach 100%.
How does that sound?
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04-26-2006, 06:50 PM
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NL20 Grinder...
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Join Date: Jul 2005
Location: Portland, OR
Posts: 7,523
Limits Played: $0.10-$0.25 NL
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Quote:
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Originally Posted by purus
Wait, I think I figured it out. 2 coins would be 75%, not 100%. I thought it was a little weird that it would go over 100%, because there is always a chance that you will get all heads.
I think that the formula is that for each coin you add, you add the original percent devided by the new total of coins. So 1 coin is 50%, 2 is 50% + (50% / 2), and three coins is 50% + (50% / 2) + (50% / 3). That way it will never reach 100%.
How does that sound?
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Like way to much math for someone like me...
This is Bonch's territory...He is the resident ubergenius... 
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