Another(fairly easy) math problem - Page 2

helmuthpoker201 · #11 (**permalink**) 06-30-2005, 09:55 PM

Quote:

Originally Posted by Av8tor009

(for physics lovers)
bonus question: what's ur velocity during both the first lap and the second lap?

lol you erased the first part of your post.

Av8tor009 · #12 (**permalink**) 06-30-2005, 09:57 PM

correct.... since you are going in circles, your velocity is always zero since delta X is always 0... thats why they call it a speedway instead of a velocityway

FindingNemo22 · #13 (**permalink**) 06-30-2005, 10:00 PM

very nice work hellmuth

helmuthpoker201 · #14 (**permalink**) 06-30-2005, 10:03 PM

How can you be moving and have your velocity be 0?

FindingNemo22 · #15 (**permalink**) 06-30-2005, 10:04 PM

maybe cuz your in a high speed turbo jet wheelchair

Av8tor009 · #16 (**permalink**) 06-30-2005, 10:12 PM

velocity is change in displacement over change in time... since change in displacement is 0, your velocity is zero.... to put it in an old term, ur going nowhere in a hurry

helmuthpoker201 · #17 (**permalink**) 06-30-2005, 10:27 PM

Seems kinda trivial

slp · #18 (**permalink**) 06-30-2005, 10:31 PM

Quote:

Originally Posted by helmuthpoker201

Seems kinda trivial

it is, merely a definition (speed vs velocity). helmuth what were you using as the average speed function? I believe it is 120/((60/x)+1)=avg speed, is that what you used?

Trons · #19 (**permalink**) 06-30-2005, 11:00 PM

Quote:

Originally Posted by helmuthpoker201

120 is the limit. If you were to graph it, your average mph would keep rising like an exponential curve but you would never reach 120.

I love math problems (I concider myself decent). However, I couldn't for the life of me figure out what the heck you were talking about. I knew you were right as I've seen this problem before but I never concidered the answer, I jst knew it wasn't the obvious one. I thought I would explain it a different way in case people are still scratching their heads over this.

In order to accomplish a average speed of 120mph in 2 miles, you have to be able to run those 2 miles in 1 min. Since your average speed on the first mile is 60mph, you know that it took one minute to complete that first mile. Even if you did the second mile at mach 10, it's still going to take some time to complete which will give you a time of 1min+ therefore you will have an average speed of less the 120mph.

I thought Velocity was defined as speed AND direction, while Acceleration was defined as a change (whether positive or negitive) in velocity. That's why phyics people always wince at the term Deceleration because there's no such thing. I have a very basic understanding of physics and it's been 15 years since I've been in a physics course.

Trons

helmuthpoker201 · #20 (**permalink**) 07-01-2005, 10:09 AM

All i was saying is if you were to graph all the possible average speeds based on how fast your second lap was, they would go up until the point 120 on your graph. That would be the graphs limit.