Thread: Hole card rank
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Old 09-14-2006, 05:33 AM
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Stu Ungar
 
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Quote:
Originally Posted by Mr.McJ
Gder is on the right track but he forgot to divide by Pi.

The actual equation is:
If A = hole card # 1 and B = hole card # 2 then:
(A + B) / Pi x 1.2 (if suited) + 0.1 (if connected.)
close but no cigar.

sqrt(A + B) (if unpaired otherwise A) / Pi x 1.2 (if suited) + 0.1 (if connected.)

If you have aces, multiply the above by 1.1321594 (the 'bullet' number)
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